read-cache.c: allocate index entries individually

The code to estimate the in-memory size of the index based on its on-disk
representation is subtly wrong for certain architecture-dependent struct
layouts.  Instead of fixing it, replace the code to keep the index entries
in a single large block of memory and allocate each entry separately
instead.  This is both simpler and more flexible, as individual entries
can now be freed.  Actually using that added flexibility is left for a
later patch.

Suggested-by: Junio C Hamano <gitster@pobox.com>
Signed-off-by: Rene Scharfe <rene.scharfe@lsrfire.ath.cx>
Signed-off-by: Junio C Hamano <gitster@pobox.com>

1 files changed, 0 insertions, 1 deletions

diff --git a/cache.h b/cache.h
index 2e6ad3604..59840a4dc 100644
--- a/cache.h
+++ b/cache.h
@@ -316,7 +316,6 @@ struct index_state {
 	struct string_list *resolve_undo;
 	struct cache_tree *cache_tree;
 	struct cache_time timestamp;
-	void *alloc;
 	unsigned name_hash_initialized : 1,
 		 initialized : 1;
 	struct hash_table name_hash;