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authorLinus Torvalds <torvalds@osdl.org>2005-11-16 09:38:46 -0800
committerJunio C Hamano <junkio@cox.net>2005-11-16 13:17:46 -0800
commitc0c35d5e419f3bf215103b1e26359aca288c2113 (patch)
treebf4e2dd133be0adb04b35f7cceec6733f4324e7c /git-grep.sh
parent7dbc2c0402d728a206d4f1bc59729bf3a5cc4455 (diff)
downloadgit-c0c35d5e419f3bf215103b1e26359aca288c2113.tar.gz
git-c0c35d5e419f3bf215103b1e26359aca288c2113.tar.xz
Disallow empty pattern in "git grep"
For some reason I've done a "git grep" twice with no pattern, which is really irritating, since it just grep everything. If I actually wanted that, I could do "git grep ^" or something. So add a "usage" message if the pattern is empty. Signed-off-by: Linus Torvalds <torvalds@osdl.org> Signed-off-by: Junio C Hamano <junkio@cox.net>
Diffstat (limited to 'git-grep.sh')
-rwxr-xr-xgit-grep.sh4
1 files changed, 4 insertions, 0 deletions
diff --git a/git-grep.sh b/git-grep.sh
index e7a35ebd7..44c16130b 100755
--- a/git-grep.sh
+++ b/git-grep.sh
@@ -39,5 +39,9 @@ while : ; do
esac
shift
done
+[ "$pattern" ] || {
+ echo >&2 "usage: 'git grep <pattern> [pathspec*]'"
+ exit 1
+}
git-ls-files -z "${git_flags[@]}" "$@" |
xargs -0 grep "${flags[@]}" -e "$pattern"