refactor find_ref_by_name() to accept const list

Since it doesn't actually touch its argument, this makes
sense.

However, we still want to return a non-const version (which
requires a cast) so that this:

  struct ref *a, *b;
  a = find_ref_by_name(b);

works. Unfortunately, you can also silently strip the const
from a variable:

  struct ref *a;
  const struct ref *b;
  a = find_ref_by_name(b);

This is a classic C const problem because there is no way to
say "return the type with the same constness that was passed
to us"; we provide the same semantics as standard library
functions like strchr.

Signed-off-by: Jeff King <peff@peff.net>
Signed-off-by: Jay Soffian <jaysoffian@gmail.com>
Signed-off-by: Junio C Hamano <gitster@pobox.com>

1 files changed, 2 insertions, 2 deletions

diff --git a/refs.c b/refs.c
index 6eb5f5384..b2a37e118 100644
--- a/refs.c
+++ b/refs.c
@@ -1628,10 +1628,10 @@ int update_ref(const char *action, const char *refname,
 	return 0;
 }
 
-struct ref *find_ref_by_name(struct ref *list, const char *name)
+struct ref *find_ref_by_name(const struct ref *list, const char *name)
 {
 	for ( ; list; list = list->next)
 		if (!strcmp(list->name, name))
-			return list;
+			return (struct ref *)list;
 	return NULL;
 }