commit.c: remove print_commit_list()

The helper function tries to offer a way to conveniently show the
last one differently from others, presumably to allow you to say
something like

	A, B, and C.

while iterating over a list that has these three elements.

However, there is only one caller, and it passes the same format
string "%s\n" for both the last one and the other ones.  Retire the
helper function and update the caller with a simplified version.

Signed-off-by: Junio C Hamano <gitster@pobox.com>

1 files changed, 4 insertions, 1 deletions

diff --git a/bisect.c b/bisect.c
index dc13319c2..02f76f0f5 100644
--- a/bisect.c
+++ b/bisect.c
@@ -646,7 +646,10 @@ static void exit_if_skipped_commits(struct commit_list *tried,
 
 	printf("There are only 'skip'ped commits left to test.\n"
 	       "The first %s commit could be any of:\n", term_bad);
-	print_commit_list(tried, "%s\n", "%s\n");
+
+	for ( ; tried; tried = tried->next)
+		printf("%s\n", oid_to_hex(&tried->item->object.oid));
+
 	if (bad)
 		printf("%s\n", oid_to_hex(bad));
 	printf("We cannot bisect more!\n");